fungsi f didefinisikan dengan rumus f(x)= px+q jika f (3)=-10 dan f(-2)=0, nilai nilai f (8)

f(x) = px+q
f(3) = -10
f(-2) = 0

f(3) = 3p+q = -10
f(-2) = -2p+q = 0

3p+q = -10 ....1️⃣
-2p+q = 0 ....2️⃣
---------------- --
3p - (-2p) + q - q = -10 - 0
3p + 2p = -10
5p = -10
p = -10/5
p = -2

Substitusikan ke 1️⃣
(3 x -2) +q = -10
-6 + q = -10
q = -10+6
q = -9

f(x) = px+q (masukkan p dan q) -»f(x) = -2x-9

f(8) = (-2x8) - 9 = -16-9 = -25
Jadi, f(8) = -25