1per 3 log 125 - 2 log 4 + log 32 ? tolong sama caranya
Matematika
firdananisa
Pertanyaan
1per 3 log 125 - 2 log 4 + log 32 ? tolong sama caranya
1 Jawaban
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1. Jawaban Taufik01
1/3 log125 - 2 log4 + log32
=1/3 log5^3 - 2 log2^2 + log2^5
=3*1/3 log5 - 2*2 log2 + 5 log2
=log5 - 4 log2 + 5 log2
=log5 + log2