Matematika

Pertanyaan

1per 3 log 125 - 2 log 4 + log 32 ? tolong sama caranya

1 Jawaban

  • 1/3 log125 - 2 log4 + log32

    =1/3 log5^3 - 2 log2^2 + log2^5
    =3*1/3 log5 - 2*2 log2 + 5 log2
    =log5 - 4 log2 + 5 log2
    =log5 + log2

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