mohon dijawab sekarang!
Matematika
sifia17
Pertanyaan
mohon dijawab sekarang!
2 Jawaban
-
1. Jawaban missdiyun
4^(x+2) = 16^(x+5)^1/3
(2^2)^(x+2) = (2^4)^(x+5)^1/3
2^(2x+4) = 2^((4x + 20)/3)
2x+4 = (4x + 20)/3
3(2x+4) = 4x+20
6x+12 = 4x+20
6x-4x=20-12
-2x = 8
x = 8 / -2
x = -4 -
2. Jawaban maricit11
4^(x+2) = 16^(x+5)^1/3
(2^2)^(x+2) = (2^4)^(x+5)^1/3
2^(2x+4) = 2^((4x + 5)/3)
2x+4 = (4x + 5)/3
3(2x+4) = 4x+5
6x+12 = 4x+5
6x-4x=5-12
-2x = -7
x = -7 / -2
x = 7/2
x = 3 1/2 :)