Matematika

Pertanyaan

Integral dari x.akar(9 + x^2) dx
Batas 0 sampai 3

2 Jawaban

  • int(0-3) x . √(9+x²) dx
    mis: u = (9+x²)
    du = 2x dx
    dx = du/2x
    x=0 >> u=9
    x=3 >> u=18
    int(9-18) x/2x . √u du
    int(9-18) 1/2 . u^½ du
    ⅓ . u . √u batas(9-18)
    ⅓ . 18 . √18 - ⅓ . 9 . √9
    6 . 3√2 - 9
    18√2 - 9
  • int(0-3) x . √(9+x²) dx mis: u = (9+x²) du = 2x dx dx = du/2x x=0 >> u=9 x=3 >> u=18 int(9-18) x/2x . √u du int(9-18) 1/2 . u^½ du ⅓ . u . √u batas(9-18) ⅓ . 18 . √18 - ⅓ . 9 . √9 6 . 3√2 - 9 18√2 - 9

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