Himpunan penyelesaian dari sistem persamaan linear tiga variabel: x/2 = y/3 = z/5 3x + 5y - 2z = 33 adalah...

x/2 = y/3 = z/5
3x + 5y - 2z = 33
kita harus fokus ke 1 variabel, misal y
x/2 = y/3
x = 2/3 y___(1)
z/5 = y/3
z = 5/3 y___(2)
masukkan pers (1) dan (2) ke 

3x + 5y - 2z = 33
3(2/3 y) + 5y - 2(5/3 y) = 33
2y + 5y -10/3 y = 33
y(7+10/3) = 33
y(80/3) = 33
80 y = 99
y = 99/80

x= 2/3 y
  = 2/3 . 99/80
  = 33/40

z = 5/3 y
   = 5/3 .99/80
   = 33/16

mohon diperiksa lagi :D