Plis yg bisa bantu jawabannya tentang persamaan linear

2x+y+z=6........pers 1
x-y+2z=9........pers 2
x+2y+z=3.......pers 3
eliminasi pers 2 dan 3
x-y+2z=9
x+2y+z=3
_____________-
-3y+z=6.......... pers 4
eliminasi pers 1 dan 2.
2x+y+z=6...................|x1|2x+y+z=6
x-y+2z=9...................|x2 |2x-2y+4z=18
______________-
3y-3z=-12........ pers 5

eliminasi pers 4 dan 5.
-3y+z=6..... |x1|-3Y+Z=6
3y-3z=-12...|x-1|-3Y+3Z=12
_____________-
-2z =-6
z=3
substitusi pers 4
-3y+z=6
-3y+3=6
-3y=6-3
-3y=3
y=-1


substitusi nilai Y dan Z ke pers 1
2x+y+z=6
2x-1+3=6
2x+2=6
2x=6-2
2x=4
x=2


jadi nilai x=2, y=-1 dan z=3