Jika A = 7log2 dan B = 2log3 tentukanlah 6log98! Tolong dong ajarin! Step by step dan alasannya dong please butuh bgtt thanks yaa

⁷log2 = a
²log7 = 1/a

⁶log 98
= ²log98 / ²log 6
= ²log(49x2) / ²log(2x3)
= ²log(7² x 2) / ²log(2x3)
= (²log7² + ²log 2) / (²log2 + ²log3)
= (2. ²log7 + ²log2) / ( ²log2 + ²log3)
= (2. 1/a + 1) / (1 + b)
= (2/a + 1) / (1 + b)

7'log 2 = a
2'log 3 = b
7'log 3 = ab

6'log 98
= 2'log 98 / 2'log 6
= 2'log (2 × 7²) / 2'log (2 × 3)
= (2'log 2 + 2 . 2'log 7) / (2'log 2 + 2'log 3)
= (1 + 2 . 1/a) / (1 + b)
= (a + 2) / a(1 + b)
= (a + 2) / (a + ab)