Matematika

Pertanyaan

suatu fungsi ditentukan dengan rumus f(×)=ax+b.jika f(3)=2 dan f(-2)=-8 maka f(×) adalah

2 Jawaban

  • f(x)= ax+b
    f(3)= a(3)+b
    2= 3a+b
    b= 2-3a

    f(-2)= a(-2)+b
    -8= -2a+2-3a
    -8-2= -5a
    5a= 10
    a= 10/5
    a= 2

    b=2-3a
    b= 2-3(2)= 2-6= -4

    f(x)= ax+b
    f(x)= 2x+(-4)
    f(x)= 2x-4
  • f(x) = ax + b

    f(3) = a(3) + b = 2
    = 3a + b = 2

    f(-2) = a(-2) + b = -8
    = -2a + b = -8

    3a + b = 2
    -2a + b = -8
    ___________ -
    5a = 10
    a = 2

    3a + b = 2
    3(2) + b = 2
    6 + b = 2
    b = -4

    f(x) = ax + b
    f(x) = 2x - 4

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